Hey guys,
Need help with a challenge math problem :p
http://drawsave.com/Rk
How would I go about solving that? I've already done the squaring and dividing and then I am confused about what to do with the double radicals, just double square?
Just got x = n, can someone confirm?
x^8n = x^5
Gotta leave now, will solve the rest once I get home
What do you need? A proof? Or values for X and N?
simple
sqrt(x * sqrt(sqrt(x))) = x^n
sqrt(x * sqrt( x^1/2)) = x^n
sqrt(x * (x^1/2)^1/2)) = x^n
sqrt(x * x^1/4) = x^n
sqrt(x^4/4 * x^1/4) = x^n
sqrt(x^5/4) = x^n
(x^5/4)^1/2 = x^n
x^5/8 = x^n
n=5/8
(2011-04-03, 05:29 PM)Pirata Nervo Wrote: [ -> ]x^8n = x^5
Gotta leave now, will solve the rest once I get home
(2011-04-04, 01:18 AM)Tim B. Wrote: [ -> ]Wolfram Alpha is your friend: http://www.wolframalpha.com/input/?i=sqr...29+%3D+x^n
(2011-04-04, 03:25 AM)pavemen Wrote: [ -> ]simple
sqrt(x * sqrt(sqrt(x))) = x^n
sqrt(x * sqrt( x^1/2)) = x^n
sqrt(x * (x^1/2)^1/2)) = x^n
sqrt(x * x^1/4) = x^n
sqrt(x^4/4 * x^1/4) = x^n
sqrt(x^5/4) = x^n
(x^5/4)^1/2 = x^n
x^5/8 = x^n
n=5/8
This is part of WA's answer:
x^(5/8) = x^n
*
*Alternate form assuming n and x are positive.
You guys are amazing
I used to excel at mathematics, but took some time to "dumb-down" a bit.
Thanks pavemen, that definitely helped!
