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Cheers Frank

I'm now using this:

 $ip = $_SERVER["REMOTE_ADDR"];


$query = $db->write_query('SELECT filter FROM '.TABLE_PREFIX. 'banfilters');
        while($result = $db->fetch_array($query))
            {
                $res .= $result['filter']."<br/>";
                if ($ip == $res)
                    {
                        echo "<div style='width:956px; height:20px; background:#FF0000; margin:auto auto;'><strong>Banned! :-(</strong></div>";
                    }
                    else
                    {
                        echo "<div style='width:956px; height:20px; background:#00FF00; margin:auto auto;'><strong>Not Banned! :-D</strong></div>";
                    } 
       
            }

But it's still returning false, even if I'm banned.

Thanks

Try this;

$ip = $_SERVER["REMOTE_ADDR"];


$query = $db->write_query('SELECT filter FROM '.TABLE_PREFIX. 'banfilters');
        while($result = $db->fetch_array($query))
            {
                if ($ip == $result['filter'])
                    {
                        echo "<div style='width:956px; height:20px; background:#FF0000; margin:auto auto;'><strong>Banned! :-(</strong></div>";
                    }
                    else
                    {
                        echo "<div style='width:956px; height:20px; background:#00FF00; margin:auto auto;'><strong>Not Banned! :-D</strong></div>";
                    } 
       
            } 

Cheers Yaldaram

It now shows I'm banned when I've banned my IP (which is correct), however when I unban myself, it doesn't return "Not Banned! :-D"

Thanks again!

Actually this might work better:

$ip = $_SERVER["REMOTE_ADDR"];

$check = $db->query("SELECT filter FROM ".TABLE_PREFIX."banfilters WHERE filter='{$ip}'");
	if(mysql_num_rows($check) != 0)
			{
				echo "<div style='width:956px; height:20px; background:#FF0000; margin:auto auto;'><strong>Banned! :-(</strong></div>";
			}else{
                echo "<div style='width:956px; height:20px; background:#00FF00; margin:auto auto;'><strong>Not Banned! :-D</strong></div>";
            } 

Replace all code with this, its clean and tested;

$ip = $_SERVER["REMOTE_ADDR"];
$query = $db->query("SELECT `filter` FROM ".TABLE_PREFIX."banfilters WHERE filter='{$ip}'");
$result = $db->fetch_field($query, "filter");

if ($result)
{
	error("Your IP is banned.");
}
else
{
	error("Its fine.");
}

Edit: Haven't seen Frank's post. I think his code will work too.

Cheers - seems to work perfectly!

One more question:

I'm using a script to help deter proxy servers which looks like this:

// Function to get the client ip address
if (!empty($_SERVER["HTTP_CLIENT_IP"]))
{
 //check for ip from share internet
 $ip = $_SERVER["HTTP_CLIENT_IP"];
}
elseif (!empty($_SERVER["HTTP_X_FORWARDED_FOR"]))
{
 // Check for the Proxy User
 $ip = $_SERVER["HTTP_X_FORWARDED_FOR"];
}
else
{
 $ip = $_SERVER["REMOTE_ADDR"];
}

However when I try echo $ip when not using a proxy, it echoes my IP correctly. However, when I try echo $ip when using a proxy server, it's formatted like this:

realip, proxyip

How could I remove the proxy IP from that?

Thanks

Bump

Cheers

Try This:

<?php
$y = $_SERVER["REMOTE_ADDR"];
$x = $_SERVER["HTTP_X_FORWARDED_FOR"];

	if (empty($x)) 
		{
			echo "Not Using Proxy. Your IP address is: $y";
		}else{
			echo "Using Proxy. Your Proxy IP is $y. Your real IP address is: $x";
		}
?>

Thanks Frank

It's telling me I'm using a proxy (which is the same ip as my real one) even when I'm not

Thanks

Try this:

<?php
$y = $_SERVER["REMOTE_ADDR"];
$x = $_SERVER["HTTP_X_FORWARDED_FOR"];

    if (!$x) 
        {
            echo "Not Using Proxy. Your IP address is: $y";
        }else{
            echo "Using Proxy. Your Proxy IP is $y. Your real IP address is: $x";
        }
?>